5(y^2)=110

Solution for 5(y^2)=110 equation:

5(y^2)=110

We move all terms to the left:

5(y^2)-(110)=0

a = 5; b = 0; c = -110;
Δ = b2-4ac
Δ = 02-4·5·(-110)
Δ = 2200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2200}=\sqrt{100*22}=\sqrt{100}*\sqrt{22}=10\sqrt{22}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{22}}{2*5}=\frac{0-10\sqrt{22}}{10}
=-\frac{10\sqrt{22}}{10}
=-\sqrt{22}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{22}}{2*5}=\frac{0+10\sqrt{22}}{10}
=\frac{10\sqrt{22}}{10}
=\sqrt{22}
$